Шпоры к ГОСу специальность Т28 - файл n1.doc
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Базы данных
База данных содержит таблицы:
s – поставщики
p - товары
sp - поставки
s_no sname status city p_no pname color city s_no p_no qty | s_no p_no qty s1 Smith 20 London p1 Nut Red London s1 p1 300 | s2 p1 300
s2 Jones 10 Paris p2 Bolt Green Paris s1 p2 200 | s2 p2 400
s3 Blake 30 Paris p3 Screw Blue Rome s1 p3 400 | s3 p2 200
s4 Clark 20 London p4 Screw Red London s1 p4 200 | s4 p2 200
s5 Adams 30 Athens p5 Cam Blue Paris s1 p5 100 | s4 p4 300
p6 Cog Red London s1 p6 100 | s4 p5 400
Какие (
может быть несколько или ни одного!) из ниже перечисленных операторов SELECT дают следующую выборку:
1) Выборка:
s_no sname city s1 Smith London
s5 Adams Athens
Варианты:
Д) SELECT s_no, sname,city FROM s WHERE city LIKE '%th%' OR sname LIKE '%th%'
2) Выборка:
s_no sname s1 Smith
s4 Clark
Варианты:
Б) SELECT s_no,sname FROM s WHERE NOT EXISTS (SELECT * FROM p WHERE city='Paris'
AND p_no NOT IN (SELECT p_no FROM sp WHERE s.s_no=sp.s_no))
Г) SELECT s_no,sname FROM s WHERE NOT EXISTS (SELECT * FROM p WHERE city='Paris'
AND NOT EXISTS (SELECT * FROM sp WHERE p.p_no=sp.p_no AND s.s_no=sp.s_no))
3) Выборка:
s_no sname sum_p s1 Smith 1300
Варианты:
В) SELECT s.s_no,sname,SUM(qty) AS sum_p FROM s,sp WHERE s.s_no=sp.s_no
GROUP BY s.s_no,sname HAVING COUNT(*)>3
4) Выборка:
s_no sname s2 Jones
s3 Blake
Варианты:
Г) SELECT s_no,sname FROM s WHERE EXISTS(SELECT s_no FROM sp WHERE s.s_no=sp.s_no GROUP BY s_no HAVING COUNT(*)<3)
5) Выборка:
s_no city status p_no qty s2 Paris 10 p1 300
s2 Paris 10 p2 400
s4 London 20 p2 200
s1 London 20 p4 200
s1 London 20 p2 200
s4 London 20 p4 300
s1 London 20 p1 300
s4 London 20 p5 400
s1 London 20 p3 400
s3 Paris 30 p2 200
Варианты:
Д) SELECT s.s_no,city,status,p_no,qty FROM s,sp WHERE s.s_no=sp.s_no AND qty>100
ORDER BY status,city DESC,qty
6) Выборка:
s_no sname s1 Smith
s3 Blake
s4 Clark
Варианты:
А) SELECT s_no, sname FROM s WHERE s_no<>'s2' AND s_no IN (SELECT s_no FROM sp
WHERE p_no IN (SELECT p_no FROM sp WHERE s_no='s2'))
Д) SELECT DISTINCT s.s_no, sname FROM s,sp x,sp y WHERE s.s_no<>'s2'
AND s.s_no=x.s_no AND x.p_no=y.p_no AND y.s_no='s2'
7) Выборка:
p_no pname p2 Bolt
p5 Cam
p6 Cog
Варианты:
А) SELECT p_no,pname FROM p WHERE p_no IN (SELECT p_no FROM sp WHERE qty<200)
OR p_no IN (SELECT p_no FROM sp WHERE s_no='s3')
Д) SELECT p_no,pname FROM p WHERE p_no IN (SELECT p_no FROM sp WHERE qty<200)
OR EXISTS (SELECT * FROM sp WHERE s_no='s3' AND sp.p_no=p.p_no)
8) Выборка:
s_no city status p_no qty s2 Paris 10 p2 400
s2 Paris 10 p1 300
s4 London 20 p5 400
s1 London 20 p3 400
s4 London 20 p4 300
s1 London 20 p1 300
s4 London 20 p2 200
s1 London 20 p4 200
s1 London 20 p2 200
s3 Paris 30 p2 200
Варианты:
А) SELECT s.s_no,city,status,p_no,qty FROM s,sp WHERE s.s_no=sp.s_no AND qty>100
ORDER BY status, city DESC, qty DESC
Б) SELECT s.s_no,city,status,p_no,qty FROM s,sp WHERE s.s_no=sp.s_no AND qty>100
ORDER BY status ASC, city DESC, qty DESC
9) Выборка:
s_no sname p_no qty s1 Smith p6 100
s1 Smith p5 100
s5 Adams null null
Варианты:
Б) SELECT s.s_no,sname,p_no,qty FROM s,sp WHERE s.s_no=sp.s_no AND qty<200 UNION
SELECT s_no,sname, NULL AS p_no, NULL AS qty FROM s
WHERE s_no NOT IN (SELECT s_no FROM sp)
В) SELECT s.s_no,sname,p_no,qty FROM s LEFT JOIN sp ON (s.s_no=sp.s_no)
WHERE qty IS NULL OR qty<200
10) Выборка:
s_no sname s1 Smith
s2 Jones
s3 Blake
s4 Clark
Варианты:
Г) SELECT s_no,sname FROM s WHERE EXISTS (SELECT * FROM p WHERE city='Paris'
AND EXISTS (SELECT * FROM sp WHERE p.p_no=sp.p_no AND s.s_no=sp.s_no))
11) Выборка:
s_no sname s1 Smith
s3 Blake
s4 Clark
s5 Adams
Варианты:
Г) SELECT DISTINCT s.s_no,sname FROM s LEFT JOIN sp ON (s.s_no=sp.s_no)
WHERE qty IS NULL OR qty=200
12) Выборка:
p_no pname p1 Nut
p2 Bolt
Варианты: Д) SELECT p_no, pname FROM p WHERE p_no IN (SELECT p_no FROM sp
WHERE sp.s_no IN (SELECT s_no FROM s WHERE city='Paris'))
13) Выборка:
s_no sname p_no pname qty s1 Smith p3 Screw 400
s2 Jones p2 Bolt 400
s4 Clark p5 Cam 400
Варианты:
Б) SELECT s.s_no,sname,p.p_no,pname,qty FROM s,sp,p WHERE s.s_no=sp.s_no
AND p.p_no=sp.p_no AND qty>300
Г) SELECT s.s_no,sname,p.p_no,pname,sp.qty FROM s,sp INNER JOIN p ON (sp.p_no=p.p_no)
WHERE qty>300 AND s.s_no=sp.s_no
14) Выборка:
s_no sname s1 Smith
s4 Clark
Варианты:
Б) SELECT s_no,sname FROM s WHERE s_no IN (SELECT s_no FROM sp
GROUP BY s_no HAVING COUNT(*)>2)
В) SELECT s.s_no,sname FROM s,sp WHERE s.s_no=sp.s_no
GROUP BY s.s_no,sname HAVING COUNT(*)>2
15) Выборка:
s_no city status p_no qty s4 London 20 p2 200
s1 London 20 p4 200
s1 London 20 p2 200
s4 London 20 p4 300
s1 London 20 p1 300
s4 London 20 p5 400
s1 London 20 p3 400
s2 Paris 10 p1 300
s2 Paris 10 p2 400
s3 Paris 30 p2 200
Варианты:
Д) SELECT s.s_no,city,status,p_no,qty FROM s,sp WHERE s.s_no=sp.s_no AND qty>100
ORDER BY city,status,qty
16) Выборка:
s_no cnt_p s1 13
Варианты:
Д) SELECT 's1' AS s_no,COUNT(*) AS cnt_p FROM (s LEFT JOIN sp ON (s.s_no=sp.s_no))
LEFT JOIN p ON p.p_no=sp.p_no
17) Выборка:
s_no sname s1 Smith
s2 Jones
s4 Clark
Варианты:
Д) SELECT DISTINCT s.s_no,sname FROM s,sp WHERE s.s_no = sp.s_no AND qty>200
18) Выборка:
p_no pname p2 Bolt
p3 Screw
Варианты:
Д) SELECT DISTINCT p.p_no,p.pname FROM p WHERE city NOT IN ('London')
AND pname NOT IN ('Cam')
19) Выборка:
s_no sname s1 Smith
s2 Jones
s3 Blake
Варианты:
В) SELECT DISTINCT s.s_no, sname FROM (s INNER JOIN sp x ON (s.s_no=x.s_no
AND s.s_no<>'s4')) INNER JOIN sp y ON (x.p_no=y.p_no AND y.s_no='s4')
AND s.s_no<>'s4')) INNER JOIN sp ON (x.p_no=y.p_no AND y.s_no='s4')
20) Выборка:
s_no sname city s3 Blake Paris
s5 Adams Athens
Варианты:
А) SELECT s_no, sname, city FROM s WHERE city LIKE '%a%' AND sname LIKE '%a%'
21) Выборка:
s_no sname city s1 Smith London
s3 Blake Paris
s5 Adams Athens
Варианты:
Д) SELECT s_no, sname, city FROM s WHERE status>20 OR sname LIKE '%th%'
22) Выборка:
s_no sname p_no pname qty s1 Smith p3 Screw 400
s1 Smith p5 Cam 100
s4 Clark p5 Cam 400
Варианты:
Д) SELECT s.s_no,sname,p.p_no,pname,qty FROM s,sp,p WHERE s.s_no=sp.s_no
AND p.p_no=sp.p_no AND status>10 AND color='Blue'
23) Выборка:
s_no sname sum_p s1 Smith 1300
s4 Clark 900
Варианты:
А) SELECT s.s_no,sname,SUM(qty) AS sum_p FROM s,sp WHERE s.s_no=sp.s_no
GROUP BY s.s_no,sname HAVING COUNT(*)>2
24) Выборка:
p_no pname p2 Bolt
Варианты:
Б) SELECT p_no,pname FROM p WHERE EXISTS (SELECT * FROM sp WHERE p.p_no=sp.p_no
AND EXISTS (SELECT * FROM s WHERE sp.s_no=s.s_no AND status>20))
25) Выборка:
s_no sname s2 Jones
s3 Blake
s5 Adams
Варианты: среди вариантов нет правильного ответа
А) SELECT s_no,sname FROM s WHERE NOT EXISTS (SELECT * FROM p WHERE city='Paris'
AND NOT EXISTS (SELECT * FROM sp WHERE p.p_no=sp.p_no AND s.s_no=sp.s_no))
Б) SELECT s_no,sname FROM s WHERE EXISTS (SELECT * FROM p WHERE city='Paris'
AND NOT EXISTS (SELECT * FROM sp WHERE p.p_no=sp.p_no AND s.s_no=sp.s_no))
В) SELECT s_no,sname FROM s WHERE EXISTS (SELECT * FROM p WHERE city='Paris'
AND EXISTS (SELECT * FROM sp WHERE p.p_no=sp.p_no AND s.s_no=sp.s_no))
Г) SELECT s_no,sname FROM s WHERE EXISTS (SELECT * FROM p WHERE city='Paris'
AND (SELECT * FROM sp WHERE p.p_no=sp.p_no AND s.s_no=sp.s_no))
Д) SELECT s_no,sname FROM s WHERE NOT EXISTS (SELECT * FROM p WHERE city='Paris'
AND p_no NOT IN (SELECT p_no FROM sp WHERE s.s_no=sp.s_no))
26) Выборка:
s_no sname s1 Smith
s2 Jones
s4 Clark
Варианты:
Г) SELECT DISTINCT s.s_no, sname FROM (s INNER JOIN sp x ON (s.s_no=x.s_no
AND s.s_no<>'s3')) INNER JOIN sp y ON (x.p_no=y.p_no AND y.s_no='s3')
27) Выборка:
s_no sname sum_p s1 Smith 1300
s2 Jones 700
s4 Clark 900
Варианты:
В) SELECT s.s_no,sname,SUM(qty) AS sum_p FROM s,sp WHERE s.s_no=sp.s_no
AND EXISTS(SELECT * FROM sp z WHERE sp.s_no=z.s_no AND sp.p_no<>z.p_no)
GROUP BY s.s_no,sname
Д) SELECT s.s_no,sname,SUM(qty) AS sum_p FROM s,sp WHERE s.s_no=sp.s_no
GROUP BY s.s_no,sname HAVING COUNT(*)>1
28) Выборка:
p_no pname p3 Screw
p5 Cam
Варианты:
Д) SELECT DISTINCT p.p_no,p.pname FROM sp,p WHERE sp.p_no=p.p_no
AND color IN ('Black','Blue','White')
29) Выборка:
s_no sname s1 Smith
s2 Jones
s4 Clark
Варианты:
А) SELECT s.s_no,sname FROM s,sp WHERE s.s_no=sp.s_no
GROUP BY s.s_no,sname HAVING COUNT(*)>=2
30) Выборка:
s_no cnt_p s1 12
Варианты:
А) SELECT 's1' AS s_no,COUNT(pname) AS cnt_p FROM (s LEFT JOIN sp
ON (s.s_no=sp.s_no)) LEFT JOIN p ON p.p_no=sp.p_no
31) Выборка:
s_no sname p_no pname qty s1 Smith p1 Nut 300
s1 Smith p4 Screw 200
s1 Smith p6 Cog 100
s4 Clark p4 Screw 300
Варианты:
Б) SELECT s.s_no,sname,p.p_no,pname,qty FROM (s INNER JOIN sp ON s.s_no=sp.s_no)
INNER JOIN p ON sp.p_no=p.p_no WHERE status>10 AND color='Red'
32) Выборка:
p_no pname p2 Bolt
p3 Screw
p5 Cam
Варианты:
Г) SELECT DISTINCT p.p_no,p.pname FROM p WHERE p_no BETWEEN 'p1'
AND 'p6' AND city NOT IN ('London')
Д) SELECT DISTINCT p.p_no,p.pname FROM sp,p WHERE sp.p_no=p.p_no AND qty>300
33) Выборка:
s_no sname p_no qty s1 Smith p5 100
s1 Smith p6 100
Варианты:
Д) SELECT s.s_no,sname,p_no,qty FROM s RIGHT JOIN sp ON s.s_no=sp.s_no
WHERE qty IS NULL OR qty<200
34) Выборка:
s_no sname s3 Blake
s5 Adams
Варианты:
А) SELECT s_no,sname FROM s WHERE s_no NOT IN (SELECT s_no FROM sp WHERE qty>200)
Б) SELECT s_no,sname FROM s WHERE NOT EXISTS
(SELECT * FROM sp WHERE s.s_no=sp.s_no AND qty>200)
35) Выборка:
s_no cnt_p s1 2
s2 2
s4 2
Варианты:
А) SELECT s_no,COUNT(*) AS cnt_p FROM p,sp WHERE p.p_no=sp.p_no AND qty>200
GROUP BY sp.s_no
Б) SELECT s_no,COUNT(DISTINCT pname) AS cnt_p FROM p INNER JOIN sp ON p.p_no=sp.p_no
WHERE qty>200 GROUP BY sp.s_no
36) Выборка:
s_no sname p_no qty s1 Smith p6 100
Варианты:
Г) SELECT s.s_no,sname,p_no,qty FROM s INNER JOIN sp ON s.s_no=sp.s_no
AND (qty IS NULL OR qty<200) WHERE p_no <> 'p5'